Question #710f4

1 Answer
Jan 11, 2017

4NH_3(g) + 5O_2(g) rarr 4NO(g) + 6H_2O(l)

Explanation:

Nitrous oxide is commonly an oxidation product of ammonia. If this is the reaction you propose, then 3 "equiv" of water result from 2 "equiv" of ammonia.

You react 40*mol of NH_3, then clearly you get 60*mol of OH_2. I acknowledge that this might not have been the reaction you had in mind.