Question

Question #eb959

Answer 1

#9 Using Polar Coordinates,

`V=int_0^(2pi) int_2^4 (16-r^2)rdrd theta=72pi`

#10 By converting to Spherical Coordinates,

`int_0^(2pi)int_0^(pi/2) int_0^1 e^(r^3) r^2sin phi dr d phi d theta=2/3 (e-1)pi`