Sum of the interior angles of a polygon is $3060^@$ . How many sides does it have?

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Answer 1 · 2017-01-09T16:07:48

The interior angle sum is $(n-2)xx180^o$ , where n is the number of interior angles.

So triangle $(3-2)xx180^o=180^o$ ,
Quadrangle $(4-2)xx180^o=360^o$ ,
Etc.

$(n-2)xx180^o=3060^o->n-2=3060^o/180^o=17->n=19$

This is also the number of sides.

Sum of the interior angles of a polygon is 3060^@3060^@. How many sides does it have?