What salt should be formed by the interaction of aluminum metal and iodine?

Question

What salt should be formed by the interaction of aluminum metal and iodine?

1 Answer

Impact of this question

2824 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-12T09:09:10

This is a poor question. They ask you to predict a formula of ${AlI}_{3}$ $"AlI"_3$ , $aluminum triiodide$ $"aluminum triiodide"$ .

Explanation:

$Aluminum$ $"Aluminum"$ is a Group 13 metal; it is commonly oxidized to the $A l^{3 +}$ $Al^(3+)$ cation:

$A l \to A l^{3 +} + 3 e^{-}$ $AlrarrAl^(3+) + 3e^-$

On the other hand, iodine is a Group 17 non-metal. It is commonly reduced to give the iodide anion:

$\frac{1}{2} I_{2} + e^{-} \to I^{-}$ $1/2I_2 + e^(-) rarr I^-$

When aluminum and iodine make music together, i.e. combine in a redox reaction, 3 equiv of electrons of electrons are transfered:

$A l + \frac{3}{2} I_{2} \to {A l^{3 +} I_{3}^{-}}$ $Al +3/2I_2rarr{Al^(3+)I_3^(-)}$ . And ${A l^{3 +} I_{3}^{-}} \equiv A l I_{3}$ ${Al^(3+)I_3^(-)}-=AlI_3$

We know that most matter is electrically neutral, and all I have done here is to draft enough iodide ions, formally anionic, to neutralize the charge of the $A l^{3 +}$ $Al^(3+)$ cation.

Science

Math

Humanities

... and beyond

What salt should be formed by the interaction of aluminum metal and iodine?

1 Answer

Explanation:

Related questions

Impact of this question