Question #878d6

1 Answer
P dilip_k
Jan 16, 2017

Molar mass of
"Fe"_2"O"_3=(2xx56+3xx16)g"/mol"=160g"/mol"

So 160g" "Fe_2O_3 contains 112g" " Fe

Hence 160"tonne "Fe_2O_3 contains 112"tonne " Fe

"Fe"_2"O"_3(s) + 3"CO"(g) -> 2"Fe"(l) + 3"CO"_2(g)

As per the given balanced equation 160 g of Fe_2O_3 produces 112 g Fe on reduction.

So 112tonnes of iron can be obtained by reducing 160 tonnes of iron (III) oxide.

Related questions
See all questions in Equation Stoichiometry
Impact of this question
1837 views around the world
You can reuse this answer
Creative Commons License