Question

Question #a303d

Answer 1

`lim_(x->oo) (1+3^x)/(1-3^x) = -1`

Explanation:

You can write the function as:

`(1+3^x)/(1-3^x) = (3^x(3^(-x) + 1))/(3^x(3^(-x) - 1)) = (3^(-x) + 1)/(3^(-x) - 1)`

As:

`lim_(x->oo) 3^(-x) = 0`

We have:

`lim_(x->oo) (1+3^x)/(1-3^x) = lim_(x->oo) (3^(-x) + 1)/(3^(-x) - 1) = -1`