Question

Question #c11af

Answer 1

`lim_(x->0) (1-cos(2x))/x^2 = 2`

Explanation:

Use the identity:

`sin^2x = (1-cos(2x))/2`

So:

`lim_(x->0) (1-cos(2x))/x^2 = lim_(x->0) 2 sin^2x/x^2 = 2 lim_(x->0)(sinx/x)^2 = 2`