Question

Under a pressure of `1.2*atm` a gas occupies an `8*mL` volume in a piston. What pressure develops if the volume is increased to `12*mL`?

Answer 1

`P_2=0.8*atm`

Explanation:

Boyle's Law holds that `P_1V_1=P_2V_2` at constant temperature.

And thus `P_2=(P_1V_1)/V_2=(1.2*atmxx8*mL)/(12*mL)=0.8*atm`.

This decrease in pressure is reasonable, given that we have INCREASED the volume.