The equation for this cell most likely is,
#A(s) + B^(2+)(aq) rightleftharpoons A^(2+)(aq) + B(s)#
Let's consider each statement in turn.
#"A"# is incorrect, galvanic cells convert chemical energy (e.g. bonds) to electrical energy (e.g. voltage).
#"B"# is incorrect. Although electrical energy is used, #A# is "dissolved" and #B"# is deposited per the notation.
#"C"# is correct. #A"# is oxidized in this cell; hence it is theoretically a stronger reducing agent.
#"D"# is incorrect. #A# is oxidized in this cell; it does no oxidizing.