Question

Question #23e3b

Answer 1

Trimethylborane.

Explanation:

So, you must find the name of

`(color(blue)("CH"_3))_color(red)(3)"B"`

Notice that the compound given to you contains `color(red)(3)` methyl groups, `color(blue)("H"_3 "C"-)`, bonded to an atom of boron, `"B"`.

You can think of these methyl groups as replacing the hydrogen atoms in borane, `"BH"_3`, which looks like this

Instead of a central boron atom bonded to three hydrogen atoms, you have it bonded to three carbon atoms.

The show that you're dealing with `color(red)(3)` methyl groups, you must use the Greek prefix tri.

You will have

`(color(blue)("CH"_3))_color(red)(3)"B" -> color(red)("tri")color(blue)("methyl")"borane"`