Question

Question #33ba6

Answer 1

Approx. `15-16*g`.

Explanation:

`"Concentration"` `=` `"Moles"/"Volume"`

And thus `"moles"` `=` `"concentration"` `xx` `"volume"`

`"moles"` `=` `0.280*mol*cancel(L^-1)xx275xx10^-3*cancelL`

`=0.0770*mol`

And thus we need a mass of `0.0770*molxx208.3*g*mol^-1`

`=` `??*g`