At "NTP" what is the mass of a 0.448*L volume of dinitrogen gas?

1 Answer
Feb 13, 2017

We take NTP as 293.15*K, and 1*atm.............

Explanation:

n="Mass"/"Molar mass"=(PV)/(RT)

Thus "Mass"=(28.02*g*cancel(mol^-1)xx1*cancel(atm)xx0.448*cancelL)/(0.0821*cancel(L*atm*K^-1*mol^-1)xx293.15*cancelK)

~~0.5*g