Question

Question #bd302

Answer 1

she bought 9 oranges.

Explanation:

Let o represent the number of oranges she bought.

Then the cost of each fruit may be expressed as.

`(7xx0.16)=₤1.12larrcolor(red)"cost of apples"`

`"and "(0.11 o)larrcolor(orange)"cost of oranges"`

Expressing the total cost as an equation.

`rArrcolor(red)(1.12)+color(orange)(0.11o)=2.11`

subtract 1.12 from both sides.

`cancel(1.12)cancel(-1.12)+0.11o=2.11-1.12`

`rArr0.11o=0.99`

To solve for o, divide both sides by 0.11

`(cancel(0.11) o)/cancel(0.11)=0.99/0.11`

`rArro=9`

`"Hence Indra bought 9 oranges"`

`color(blue)"As a check"`

The total cost of apples and oranges should be ₤2.11

`(7xx0.16)+(9xx0.11)=1.12+0.99=₤2.11color(white)(xx)✔︎`