Question

Question #8deff

Answer 1

The limit is `0`.

Explanation:

`lim_(xrarr3^+)(x-3)/sqrt(x^2-9) = lim_(xrarr3^+)((x-3)sqrt(x^2-9))/(x^2-9)`

`= lim_(xrarr3^+)((x-3)sqrt(x^2-9))/((x-3)(x+3))`

`= lim_(xrarr3^+)sqrt(x^2-9)/(x+3)`

`= 0/6 = 0`