Between which two consecutive integers does the square root of $36$ $36$ lie?

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Between which two consecutive integers does the square root of $36$ $36$ lie?

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Answer 1 · 2017-02-01T23:25:21

$\sqrt{36} = 6$ $sqrt(36) = 6$ lies between consecutive odd integers $5$ $5$ and $7$ $7$ .

Explanation:

"The" square root of $36$ $36$ is itself an integer, namely $6$ $6$ , since $6^{2} = 36$ $6^2 = 36$ . So it does not lie between consecutive integers.

It does lie between consecutive odd integers $5$ $5$ and $7$ $7$ .

Note that $36$ $36$ has another square root, namely $- 6$ $-6$ , since $- 6$ $-6$ satisfies:

${(- 6)}^{2} = 36$ $(-6)^2 = 36$

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Between which two consecutive integers does the square root of $36$ $36$ lie?

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Science

Math

Humanities

... and beyond

Between which two consecutive integers does the square root of 3636 lie?

1 Answer

Explanation:

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Impact of this question

Between which two consecutive integers does the square root of $36$ $36$ lie?