Question

Question #86fe6

Answer 1

`lim_(x->0) (x^3+2x)/e^(3x) = 0`

Explanation:

As for `x=0` the denominator `[e^(3x)]_(x=0) = e^0 = 1` is not null, the function is continuous and:

`lim_(x->0) (x^3+2x)/e^(3x) = [(x^3+2x)/e^(3x)]_(x=0) = 0`