Question #c6847
1 Answer
Aug 20, 2017
Explanation:
#"given "csctheta=3" then"#
#•color(white)(x)sintheta=1/csctheta=1/3#
#"since "sintheta>0" this indicates that "theta# is in the first or second quadrant.
#•color(white)(x)costheta=+-sqrt(1-sin^2theta)#
#color(white)(xxxxxx)=-sqrt(1-1/9)=-sqrt(8/9)#
#color(white)(xxxxxx)=-(2sqrt2)/3#
#•color(white)(x)sectheta=1/costheta=-1/((2sqrt2)/3)=-3/(2sqrt2)=-(3sqrt2)/4#
#•color(white)(x)tantheta=sintheta/costheta=(1/3)/(-(2sqrt2)/3)=-1/(2sqrt2)=-sqrt2/4#
#•color(white)(x)cottheta=1/tantheta=1/(-sqrt2/4)=-4/sqrt2=-2sqrt2#
#theta" is in the second quadrant"#