Question #c045e

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Question #c045e

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Answer 1 · 2017-07-08T10:45:02

option (2)

Explanation:

$0 C l_{2} + + 1 N a - 2 O + 1 H \to + 1 N a + 5 C l {- 2 O}_{3} + + 1 N a - 1 C l + {+ 1 H}_{2} - 2 O$ $stackrel0Cl_2+stackrel(+1)Na stackrel(-2) O stackrel(+1)H->stackrel(+1)Na stackrel(+5)Clstackrel(-2)O_3+stackrel(+1)Na stackrel(-1)Cl+stackrel(+1)H_2stackrel(-2)O$

This is a disproportionation reaction where same element $C l$ $Cl$ gets oxidised as well as reduced.

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Question #c045e

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