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Question #588ae

1 Answer

Feb 10, 2017

The reaction equation is $N_{2} + 3 H_{2} \to 2 N H_{3}$ $N_2+3H_2->2NH_3$

Explanation:

So for every mol of $N_{2}$ $N_2$ you need 3 mol of $H_{2}$ $H_2$ .

Answer: $3 \times 2.0 = 6.0 m o l H_{2}$ $3xx2.0=6.0molH_2$

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