Question #8dc0a

Question

1513 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-12T09:35:37

Given

#"Mass of the ball "m=300g=0.3kg#

#"Initial velocity of the ball "u=-8m"/"s#

#"Final velocity of the ball "v=+6m"/"s#

#"Force applied on the ball by the wall "F=2000N#

#"Let the time of ball-wall contact be "=t s#

So by Newton's law we have

#F=(m(v-u))/t#

#=>2000=(0.3xx(6-(-8)))/t#

#=>t=4.2/2000=2.1xx10^(-3)s=2.1ms#