Find te value of ${csc}^{- 1} (- 2)$ $csc^(-1)(-2)$ ?

Question

1140 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-29T16:29:28

${csc}^{- 1} (- 2) = - \frac{π}{6}$ $csc^(-1)(-2)=-pi/6$

Let ${csc}^{- 1} (- 2) = A$ $csc^(-1)(-2)=A$

then $csc A = - 2$ $cscA=-2$

or $\frac{1}{sin A} = - 2$ $1/sinA=-2$

or $sin A = - \frac{1}{2} = sin (- \frac{π}{6})$ $sinA=-1/2=sin(-pi/6)$

i.e. $A = - \frac{π}{6}$ $A=-pi/6$

Hence ${csc}^{- 1} (- 2) = - \frac{π}{6}$ $csc^(-1)(-2)=-pi/6$

Find te value of csc−1(−2)csc^(-1)(-2)?