Question

Question #7bb02

Answer 1

Given expression is
`y= 3e^x+ 4/(root(3)(x)`
`=>y= 3e^x+ 4(x)^(-1/3)`
Differentiating
`y'= d/dx(3e^x+ 4(x)^(-1/3))`
`=>y'= d/dx(3e^x)+ d/dx(4(x)^(-1/3))`
`=>y'= 3e^x+ 4xx(-1/3)(x)^(-1/3-1)`
`=>y'= 3e^x- 4/3(x)^(-4/3)`
`=>y'= 3e^x- 4/(3(x)^(4/3))`
`=>y'= 3e^x- 4/(3root(3)(x^4)`