Question #07b8f
1 Answer
Explanation:
A solution's molality is simply a measure of how many moles of solute you get for every
In your case, a
You can thus use the molality of the solution as a conversion factor to help you figure out how many moles of solute you need to have in
#250 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.250 kg"#
of water in order to have a
#0.250 color(red)(cancel(color(black)("kg water"))) * overbrace("3.0 moles BaCl"_2/(1color(red)(cancel(color(black)("kg water")))))^(color(blue)("= 3.0 m")) = color(darkgreen)(ul(color(black)("0.75 moles BaCl"_2)))#
The answer is rounded to two sig figs.