Question #672cd

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Answer 1 · 2017-02-24T07:33:16

$y = -x+4 and y = 1/4x+14$

Slope-intercept form of the equation of a straight line is $y = mx+c$

$-1.1x-5.5y = -4.4" "larr$ re-arrange the equation

$color(white)(........) -5.5y = 1.1x -4.4" "larr$ divide by $-1.1$

$color(white)(..................)y = -x+4$

Do the same for the other equation:

$0.8x-3.2y = -11.2" "larr$ re-arrange the equation

$color(white)(.....)-3.2y = -0.8x-11.2" "larr$ divide by $-3.2$

$color(white)(................)y = 0.25x+14$

$color(white)(................)y = 1/4x+14$

Now plot the graphs.

The break-even point can be found from the point of intersection of the the two lines.
graph{(-x-y+4)(x/4-y+14)=0 [-21.75, 18.25, -2.72, 17.28]}