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Answer 1 · 2017-02-24T14:20:01

Treating horizontal and vertical motions independently as these are orthogonal.
Time taken to cover $100 m$ $100m$ with initial horizontal velocity of $500 m s^{- 1}$ $500ms^-1$
$t = \frac{Distance}{Velocity} = \frac{100}{500} = 0.2 s$ $t="Distance"/"Velocity"=100/500=0.2s$

The bullet falls freely under gravity in vertical direction with initial velocity of $0$ $0$ . Vertical defection in vertical in $0.2 s$ $0.2s$ is found using the kinematic equation
$d = u t + \frac{1}{2} g t^{2}$ $d=ut+1/2g t^2$
$\Rightarrow d = 0 \times 0.2 + \frac{1}{2} \times 9.81 \times {(0.2)}^{2} \approx 0.196 m$ $=>d=0xx0.2+1/2 xx9.81xx (0.2)^2~~0.196m$
$\Rightarrow d = \approx 0.196 m$ $=>d=~~0.196m$

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