How does $"sodium oleate"$ react with $HCl$ ?

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Answer 1 · 2017-03-02T08:43:20

This is an acid base reaction..........

Here, $"sodium oleate"$ is the conjugate base of a weak acid, and so:

$C_17H_33CO_2^(-)""^(+)Na(aq) + HCl(aq) rarr C_17H_33CO_2H(aq) + NaCl(aq)$

The product acid, $"oleic acid"$ , is the principal component of olive oil: it probably has next to no solubility in water.

How does "sodium oleate""sodium oleate" react with HClHCl?