Question

Question #8a5b0

Answer 1

`LHS=(sinx/(1-cosx) + sinx/(1+cosx))`

`=(sinx(1+cosx) + sinx(1-cosx))/((1-cosx)(1+cosx))`

`=(sinx+sinxcosx + sinx-sinxcosx)/(1-cos^2x)`

`=(2sinx)/sin^2x=2/sinx=2cscx=RHS`

Proved