Question

Question #950a6

Answer 1

`I=44sin(theta)+44sin(theta+pi/14)`

Using formula
`sinC+sinD=2sin((C+D)/2)cos((C-D)/2)`

`=>I=44(sin(theta)+sin(theta+pi/14))`

`=>I=44*2sin(theta+pi/28)cos(pi/28)`

`=>I=88cos(pi/28)sin(theta+pi/28)`

`=>I=Rsin(theta+a)`

Where `R=88cos(pi/28) and a= pi/28`