Question

Question #56c3d

Answer 1

`t=(ks)/e`

Explanation:

This will be a variant on `y=kx`

The one thing that will be in both is the need for a constant of variation `k`

What is happening? as the number of exits increases it should be the case that the people exit faster. Thus `t` will reduce

Let the total time of completed exist be `t`
Let the count of exits be `e`
Let the count of people (for this consideration) be the constant `s`

Then as `E` increases we need `t` to reduce

Logically we would have `t->s/e`

However this would need to incorporate some way of allowing for adjustment. This is where `k` comes in. Write as:

`t=kxxs/e" "->" "t=(ks)/e`
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Note that the choice of the variant `e` is not one I would have picked. In mathematics `e` is a recognised constant that is reserved.

It is used a lot in log to base `e" "->log_e" "->" "ln`