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Question #3ef14

1 Answer

sankarankalyanam

Oct 25, 2017

$P e r i m e t e r = (6 b^{2} + 4 b - 13) c m$ $Perimeter = (6b^2+4b-13) cm$

Explanation:

Perimeter of a triangle = sum of the three sides.

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We know $A B = A C = 3 b^{2} - 4$ $AB = AC = 3b^2 - 4$ & $B C = 4 b - 5$ $BC = 4b - 5$

$:. Perimeter = 2(3b^2 - 4) + (4b - 5)$

$Perimeter = 6b^2 - 8 +4b - 5 = (6b^2 + 4b - 13) cm$

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