Question

Question #78bc0

Answer 1

`6sin^4x`

`=6/4xx(2sin^2x)^2`

`=3/2xx(1-cos2x)^2`

`=3/2xx(1-2cos2x+cos^2 2x)`

`=3/2xx(1-2cos2x+1/2(1+cos4x))`

`=3/4xx(3-4cos2x+cos4x))`