How do we simplify #sintheta/sin(theta + pi/2)#?
1 Answer
Mar 4, 2017
The expression equals
Explanation:
We can expand the denominator using
#sintheta/(sinthetacos(pi/2) + sin(pi/2)costheta)#
#sintheta/((0)sin theta + 1(costheta)#
#sintheta/costheta#
Use
#tantheta#
Hopefully this helps!