Question

Question #33f91

Answer 1

`int_0^(pi/4)secx^2tanxdx=1/2`

Explanation:

Perhaps you mean `int_0^(pi/4)secx^2tanxdx`

To find this assume `u=tanx`, then `du=sec^2xdx` and

Observe that as `tan0=0` and `tan(pi/4)=1`, the new limits are `0` and `1` and

`int_0^(pi/4)secx^2tanxdx=int_0^1udu`

= `[u^2/2]_0^1`

= `1/2-0=1/2`