How do we represent the reaction of potassium iodide with lead nitrate in aqueous solution?

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Answer 1 · 2017-03-07T08:04:16

This is a $metathesis$ $"metathesis"$ , partner exchange reaction, that results in the formation of an INSOLUBLE precipitate.

And how to find the physical state BUT by experiment?

$P b {(N O_{3})}_{2} (a q) + 2 K I (a q) \to P b I_{2} (s) ⏐ ↓ + 2 K N O_{3} (a q)$ $Pb(NO_3)_2(aq) + 2KI(aq) rarr PbI_2(s)darr + 2KNO_3(aq)$

Perform the reaction and you observe a canary yellow precipitate of lead iodide, which is quite insoluble in aqueous solution.

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The net ionic equation is:

$P b^{2 +} + 2 I^{-} \to P b I_{2} (s) ⏐ ↓$ $Pb^(2+) + 2I^(-) rarr PbI_2(s)darr$

This is a good qualitative test for the presence of iodide ions.