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Answer 1 · 2017-03-08T04:54:29

#log(1)=0#

A logarithm is used solve for the exponent of a base that results in a certain value.

Given:

#a^x=y#

then,

#log_a(y)=x#

For a generic 'log' function, it is assumed to be base 10. So, we have the following:

#log(1)# is like saying #10^x=1#

For any base, including 10, raised to the power 0, the result is 1. Therefore, #log(1)=0#