Question #4ea07

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Answer 1 · 2017-03-13T03:45:37

Denver nickel is valued at $$ 9$ $$9$ , and Philadelphia is valued at $$ 6$ $$6$ .

Given: The $D$ $D$ nickel has a higher value than the $P$ $P$ nickel because the fraction size is larger than $1$ $1$ . We have two unknown values.

We can write: $D = \frac{3}{2} P$ $D = 3/2 P$

We also know that $D + P = $ 15$ $D + P = $15$

Then we can substitute the $P$ $P$ value for $D$ $D$ from the first equation into the second:

$\frac{3}{2} P + P = $ 15$ $3/2 P + P = $15$

$\frac{5}{2} P = $ 15$ $5/2 P = $15$

$5 P = $ 30$ $5P = $30$

$P = $ 6$ $P = $6$

$D = \frac{3}{2} P$ $D = 3/2 P$

$2 D = 3 ($ 6)$ $2D = 3($6)$

$2 D = $ 18$ $2D = $18$

$D = $ 9$ $D = $9$

Check: $D + P = $ 15$ $D + P = $15$

$$ 9 + $ 6 = $ 15$ $$9 +$6 = $15$