Question

Question #a9c64

Answer 1

Your graph should look something like:

Explanation:

I am assuming that you meant `color(red)3/color(blue)5` to be the slope.

Plot a point for the `y` intercept of `-9` at `(0,-9)`

From the intercept point `(0,-9)` move `color(blue)5` units to the right (in the positive `x` direction) then up `color(red)3` units (in the positive `y` direction); that should put you at `(5,-6)`; plot a second point at this location.

To help verify your results, repeat this process: right `color(blue)5` and up `color(red)3` to give a third point at `(10,-3)`

Draw a straight line through the points you have plotted to obtain the required graph.