Question #62924

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Question #62924

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Answer 1 · 2017-03-11T06:14:03

When steam is passed over red hot coke (C), it ( $H_{2} O$ $H_2O$ ) gets reduced hydrogen $H_{2}$ $H_2$ and carbon is oxidized to $C O$ $CO$ producing a gas mixture of $C O (g)$ $CO(g)$ and $H_{2} (g)$ $H_2(g)$ ,known as water gas.

$C (s) (red hot) + H_{2} O (g) \to C O (g) + H_{2} (g)$ $C(s)("red hot") +H_2O(g)-> CO(g) + H_2(g)$

$Delta H=+131"kJ/mol"->"endothermic reaction"$

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Question #62924

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