Question #84631

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Question #84631

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Answer 1 · 2017-03-14T20:14:54

$80. g$ $"80. g"$

Explanation:

Since sodium hydroxide is a strong base and hydrochloric acid is a strong acid, they both completely dissociate when dissolved in water.

In a strong acid-strong base reaction, the moles of hydrogen ions must equal the moles of hydroxide ions in order to create a neutral solution.

$HCl + NaOH \to NaCl + H_{2} O$ $"HCl" + "NaOH" -> "NaCl" + "H"_2"O"$

Divide the $73 g$ $"73 g"$ of $HCl$ $"HCl"$ by its molar mass of $36.46 g/mol$ $"36.46 g/mol"$ to convert that value to moles

$\frac{73 g}{36.46 g/mol} = 2.002 moles$ $"73 g"/"36.46 g/mol" = "2.002 moles"$

Then, using the fact that the moles of hydrochloric acid equal the moles of sodium hydroxide, we know that there are $2.002$ $2.002$ moles of $NaOH$ $"NaOH"$ .

We would multiply that $2.002$ $2.002$ by the molar mass of $NaOH$ $"NaOH"$ of $39.997 g/mol$ $"39.997 g/mol"$ to get

$2.002 moles \cdot 39.997 g/mol = 80. g NaOH$ $"2.002 moles" * "39.997 g/mol" = "80. g NaOH"$

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Question #84631

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