An hydrate of $BaCl_2$ contains $0.750mg$ of the salt, and $0.0965g$ of water, how many waters in the formula $BaCl_2*n(H_2O)$ ?

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Answer 1 · 2017-03-21T16:36:48

$"Molar quantity"="Mass of substance"/"Molar mass of substance"$

$"Moles of barium chloride"=(0.00075*g)/(208.23*g*mol^-1)=??*mol$

$"Moles of water"=(0.0965*g)/(18.02*g*mol^-1)=7.203xx10^-6*mol$

And you can tell us the molar ratio..........

An hydrate of BaCl_2BaCl_2 contains 0.750*mg0.750*mg of the salt, and 0.0965*g0.0965*g of water, how many waters in the formula BaCl_2*n(H_2O)BaCl_2*n(H_2O)?