Question #00dfc Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Narad T. Oct 17, 2017 The first three output values are #(-2+2i)#, #(-3+6i)#, and #(-30+38i)# Explanation: #i^2=-1# Use #z=1# as the first input value #F(z)=z^2-3+2i# #F(1)=1-3+2i=-2+2i# Then #z=-2+2i# #F(-2+2i)=(-2+2i)^2-3+2i=(2-2i)^2-3+2i# #=4-8i+4i^2-3+2i# #=4-8i-4-3+2i# #=-3-6i# And finally #z=-3-6i# #F(-3-6i)=(-3-6i)^2-3+2i# #=9+36i^2+36i-3+2i# #=-30+38i# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1021 views around the world You can reuse this answer Creative Commons License