Question

Question #b1c7e

Answer 1

The Range is `[0,2]={ x in RR : 0 le x le 2.}`

Explanation:

Observe that, `AA x in RR, -1 le sin x le 1.`

Adding `1` throughout the inequality, we have,

`AA x in RR, -1+1 le sinx +1 le 1+1, i.e.,`

`AA x in RR, 0 le F(x) le 2.`

Hence, the Range is `[0,2]={ x in RR : 0 le x le 2.}`