Question #353c0 Chemistry Chemical Equilibrium Equilibrium Constants 1 Answer Ratnesh Bhosale Mar 17, 2017 #K_p = 2.25# Explanation: #Delta_r G= Delta_r G^0 + RT ln Q# The reaction is occurring at standard conditions then #Delta_r G^0=0# and #Q= K_(eq)# #Delta_r G= RT ln Q# #176.31 = 0.0821 xx 298 xx ln Q# # ln Q = 7.2063# # Q =1347.895# # Q =K_(eq)=1347.895# #K_p = K_c (RT)^(Delta ng)# #K_p = 1347.895xx (0.0821 xx 298)^(-2)# #K_p = 1347.895xx (24.4658)^(-2)# #K_p = 1347.895/ (24.4658)^(2)# #K_p = 1347.895/ 598.5753# #K_p = 2.2518# #K_p = 2.25# Answer link Related questions How does the equilibrium constant change with temperature? How do you find equilibrium constant for a reversable reaction? Question #a90d2 What is the equilibrium constant for the reaction of NH3 with water? What is the equation for finding the equilibrium constant for a chemical reaction? What is the equilibrium constant for the weak acid KHP? Consider this equilibrium: I2(s) + H2O(l) ⇌ H+(aq) + I-(aq) + HOI(aq). What is the Keq... What is the equilibrium constant for water? What is the equilibrium constant of citric acid? What is the rate of production of reactants compared with the rate of production of products at... See all questions in Equilibrium Constants Impact of this question 1508 views around the world You can reuse this answer Creative Commons License