Question

Question #3dc90

Answer 1

`= -(1)/(2y^2) + C`

Explanation:

Use the power rule:

`int \ y^n \ dy = (y^(n+1))/(n+1) + C`

Here you have:

`int \ 1/y ^3 \ dy = int \ y ^ (-3) \ dy = (y^(-3+1))/(-3+1) + C`

`= (y^(-2))/(-2) + C`

`= -(1)/(2y^2) + C`