Question #7af81

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Question #7af81

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Answer 1 · 2017-03-18T13:36:59

$sin t = \pm \frac{4}{5}$ $sin t = +- 4/5$

Explanation:

$cos t = \frac{3}{5}$ $cos t = 3/5$
${sin}^{2} t = 1 - {cos}^{2} t = 1 - \frac{9}{25} = \frac{16}{25}$ $sin^2 t = 1 - cos^2 t = 1 - 9/25 = 16/25$
$sin t = \pm \frac{4}{5}$ $sin t = +- 4/5$
There are 2 opposite values of sin t.
On the trig unit circle:
$cos t = \frac{3}{5}$ $cos t = 3/5$ --> $t = \pm 53^{\circ} 13$ $t = +- 53^@13$ -->
a. If t = 53.13 --> $sin t = \frac{4}{5}$ $sin t = 4/5$
b. If t = - 53.13 --> $sin t = - \frac{4}{5}$ $sin t = - 4/5$

Answer 2 · 2017-03-18T14:07:47

$\frac{4}{5}$ $4/5$ or $0.8$ $0.8$

Explanation:

$cos θ = \frac{3}{5} = 0.6$ $Cos theta=3/5=0.6$

$:.Arc cos(Cos^-1)0.6=(53.13010235°) 53°7'48.37''$

$:.theta=53°7'48.37''$

$:.Sin theta=0.8$ or $4/5$

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Question #7af81

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