Question #58265

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Answer 1 · 2017-03-18T16:53:22

$tan x = \frac{o p p o s i t e}{a d j a c e n t} = 5$ $tanx=(opposite)/(adjacent)=5$

$cot x = 0.2$ $color(red)(Cotx=0.2$ , $tan x ?$ $color(red)(tanx?$

In a right $△$ $triangle$ there is a slope side-hypotenuse,
opposite side and adjacent side.

$:.cotx=0.2=1/5$

$:.cotx=(adjacent)/(opposite)$ , $adjacent=1$ $opposite=5$

$:.tanx=(opposite)/(adjacent)$

$:.tanx=5/1$

$:.color(red)(tanx=5$

on calculator:

$:.arctan(tan^-1)0.2=11.30993247°=11°18'35.7''$

$:.tan11.30993247=0.199999713$ $=0.2$ to the nearest 1 decimal

$:.0.199999713 1/x =5.000007173= cotx$