Question #2603d

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Answer 1 · 2017-03-20T15:55:27

The gas reached a pressure of 2.5 atm.

Since the volume is constant but the pressure and temperature are changing, this is an example of Gay-Lussac's Law:

$color(blue)(bar(ul(|color(white)(a/a) P_1/T_1=P_2/T_2color(white)(a/a)|)))" "$

We can rearrange the above formula to get

$P_2=P_1 × T_2/T_1$

Your data are:

$P_1 = "1 atm"$
$T_1 = "(20 + 273.15) K"color(white)(l) = "293.15 K"$
$P_2 = "?"$
$T_2 = "(473 + 273.15) K" = "746.15 K"$

$P_2 = "1 atm" × (746.15 color(red)(cancel(color(black)("K"))))/(293.15 color(red)(cancel(color(black)("K")))) = "2.5 atm"$

The new pressure is 2.5 atm.