Question #e4692

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Answer 1 · 2017-05-29T08:11:39

2.675 grams of Helium.

995 torr equals 1.309 atm (P).
T is $173.15+25 = 298.15$ K
Now we can use this formula (The ideal gas law)

$P*V = n*R*T$

$1.309*12.5 = n*0.082056*298.15$

$n = 0.6688$ moles of Helium.

Since Helium has a mass of 4 g/mol, you can compute

$Mass = 0.6688*4$

$Mass = 2.675$ grams of Helium.