Question #fff79

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Question #fff79

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Answer 1 · 2017-03-21T00:53:43

$x = - y^{2} + y$ $x=-y^2+y$

$x = y^{2} - 3$ $x=y^2-3$

$x = - 4$ $x=-4$
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$V = π \int_{- 1}^{1.5} [{(- y^{2} + y - (- 4))}^{2} - {(y^{2} - 3 - (- 4))}^{2}] d y$ $V=piint_(-1)^(1.5)[(-y^2+y-(-4))^2-(y^2-3-(-4))^2]dy$

$= \frac{875 π}{32}$ $=(875pi)/32$

$= 85.90292412$ $= 85.90292412$

Answer 2 · 2017-03-22T01:33:48

"Find the volume of the solid obtained by rotating the region bounded by the curves $y = x^{3}$ $y=x^3$ , the $x$ $x$ -axis and the lines $x = 1$ $x=1$ and $x = 2$ $x=2$ turn around the x-axis."
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$V = π \int_{1}^{2} {(x^{3})}^{2} d x$ $V=piint_1^2(x^3)^2dx$

$= π \int_{1}^{2} (x^{6}) d x$ $=piint_1^2(x^6)dx$

$= π {[\frac{1}{7} x^{7}]}_{1}^{7}$ $=pi[1/7x^7]_1^2$

$= \frac{2^{7}}{7} - \frac{1}{7}$ $=2^7/7-1/7$

$= \frac{255 π}{7}$ $=(255pi)/7$

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Question #fff79

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