Question

Question #a3df0

Answer 1

Undetermined.

Explanation:

`sum_(k=1)^n(sin(6k)-sin(6(k+1)) = sin(6)-sin(6(n+1))`

so

`lim_(n->oo)sum_(k=1)^n(sin(6k)-sin(6(k+1)) = sin(6)-lim_(n->oo)sin(6(n+1))`

which is undetermined.